Have you ever cracked AA with AA?

[BelFish]

Here is the promised screenshot:



And also a screenshot of another rare spot:

 

[whitetailbuck10]

That's an awesome story. I couldn't imagine being either of you!!!

 

[Comboss599]

Never i think but i've seen situation AA against AA when one player won by the flush. That must've been cracked.

 

[No Bologna]

AA crack AA

Can't remember if I've done it. Seen it happen several times. Hurts when you're on the short end.

 

[BelFish]

Can't remember if I've done it. Seen it happen several times. Hurts when you're on the short end.

On the screenshot that i posted a little higher, you were sitting at the table and saw that hand )))

 

[forrow10]

I was playing a PKO yesterday and looked down at AA from EP. It was raised by a loose player and I 3 bet. The button cold 4 bets. The original raiser folds and I can either 5 bet jam or flat and see a flop. In this instance, I 5 bet jammed and got called by AA. I kind of laughed because what are the chances right. But then the flop came with 2 spades (I had the ace of spades) and I could feel that it was going to be one of those sick hands. Sure enough, turn and river were both spades. How crazy is that?

I have a similar situation in fast tables, but I got the bad pair .... I lost AA vs AA with that coloured hand.

 

[BelFish]

In the evening i will calculate the exact probability of seeing such a bad beat at the 9-max table. Just out of curiosity. I love to practice calculations

In the meantime, anyone can try to guess what this probability will be. Well, or you can try to calculate it yourself...

 

[IADaveMark]

In the evening i will calculate the exact probability of seeing such a bad beat at the 9-max table. Just out of curiosity. I love to practice calculations

In the meantime, anyone can try to guess what this probability will be. Well, or you can try to calculate it yourself...

Come at me, bro,


The only way that AA vs AA beat happens is through a flush. There is a 0.1965% chance of a flush. (You can see that in the vid where each player has 2% equity pre-flop.)

Multiply that by 2 for the 2 suits that one player covers and you get about 0.4% of them running out a flush with one of their cards. But that's heads up. You have to then calculate the odds of another player having the exact same pair as you. That is 1 in 463 or about 0.033% at a 10-handed table.

So, multiplying that by the odds of them flushing out is 0.033 * 0.4 = 0.0132

Therefore, if you have AA, the odds of someone else also having AA and flushing out on you is 1.32%.

 

[ebazynski]

I've been on both sides of this AA vs AA outcome. Had to laugh at my good fortune when I won, and of course was shocked ("are you f..ing kidding me!") when losing this way.

 

[BelFish]

Well, i meant the case when the cards have not yet been dealt. And the probability of seeing AA vs AA, that is, that any 2 players at the table can have aces

 

[hobojim1247]

I was playing cash and got all in with both red aces. The other guy called and being a cash game neither of us exposed our hands. The board ran out 5 hearts to the K. He flipped over black aces with the remark of a chopped pot. I actually slow rolled him intentionally as he was a nasty , rude, disrespectful, unlikable player who regularly belittled other players even when he won. The table went ROTFLTAO when I slow rolled my red aces. That is the only time I ever slow rolled anyone, and it couldn't have been to a more deserving person.

Jim

 

[IADaveMark]

Well, i meant the case when the cards have not yet been dealt. And the probability of seeing AA vs AA, that is, that any 2 players at the table can have aces

Oh... 1 in 463. (10-handed... slightly less at 9-handed)

 

[BelFish]

I got this result:

P = 36*(4/52 * 3/51)*(2/50 * 1/49)*4*[C(5 of 12) + 48*C(4 of 12)]/C(5 of 48) = 0.000133*4*[792+23760]/1712304 = 0.000133*0.0573543 = 0.00000763 or 0.00076%

About 1 time on each 131.000 hands.

 

[BelFish]

This is exactly the probability of seeing such a hand at a 9-max table, no matter who of the players will have aces and who will win with any of the 4 possible flushes. Only in case if everyone else folds.

C(k of n) - notation for the number of possible combinations of k elements out of n.

C(2 of 9 players) = 9/2 * 8/1 = 36 ways to deal AA hands to any 2 out of 9 players.

 

[TerryBLE]

I've seen it happening, all combinations will happen, but when the chance is very small we have the impression that "it won't even happen", but it will. :deal:

 

[smallfrie]

Yes, but not even close to the number of times I have had aces cracked by aces.

 

[exer888]

It's a bit more crazy when you are in a $1,000,000 buy-in event.

https://www.youtube.com/watch?v=iFR5i6RtX18

I remmember this hand, when i first time saw that. Imagine the feeling at that stake,i belive i couldnt come to reason mind in a couple of years. I would just retire of poker for ever.

 

[BelFish]

Imagine the feeling at that stake,i belive i couldnt come to reason mind in a couple of years. I would just retire of poker for ever.

Well, they probably played by the rules of the BRM. Just a loss of one buy-in...

 

[BelFish]

[FONT=NotoSans, Lato, arial, sans-serif]I made a mistake above. It is necessary to multiply by (48-12) instead of 48 for cases when there are 4 cards of the same suit on the board.

So, we get the following result for the probability of seeing a hand in which aces lose to aces:[/FONT]

P = 36*(4/52 * 3/51)*(2/50 * 1/49)*4*[C(5 of 12) + (48-12)*C(4 of 12)]/C(5 of 48) = 0.000133*4*[792+17820]/1712304 = 0.000133*0.043478 = 0.0000057826 or < 0.0006%

About 1 time on each 173.000 hands.

AA vs AA will happen once every 7520 hands at a 9-max table. And flash will happen exactly 1 time out of 23.

7520*23 ~ 173.000

And if we already have AA in our hands, then every 1225 hands someone will also have aces and one of the two players will get a flush 1 time out of 23. This will happen 1 time every 28175 hands. Thus, the probability of our losing with AA to another player with AA, calculated preflop, is approximately 1 of 56000.

If the cards are already turned over and both players have AA, then the probability of losing each of the players is exactly 1/46, if we do not take into account the discarded cards of other players, that is, if we do not know them.

 

[ADRI7HO]

It's a bit more crazy when you are in a $1,000,000 buy-in event.

https://www.youtube.com/watch?v=iFR5i6RtX18

Losing out with A,A against A,A is one of the roughest things. Luckily, maybe once it happened to me (and it wasn’t a $ 1 Million tournament) and it felt awful. I can’t even imagine how awful it could have been to experience this with a $ 1M buy-in in mind.

 

[0546474]

In fact, such cases are not so rare, at least for me, I both won with AA against AA and lost in a similar situation !!!

 

[BelFish]

Well, it means either you play a lot of hands, or such frauds are used in the poker room )))

I mean, if for example, it happens at a distance of 1 million hands with a frequency of every 20.000 or even 10.000 hands, and not with right frequency...

 

[Tigroslav]

Not exactly sure on the number of times but I think I did it once or twice had it happen to me once or twice and seen it happen to others a few times as well.

 

[thedarkman]

I was playing a PKO yesterday and looked down at AA from EP. It was raised by a loose player and I 3 bet. The button cold 4 bets. The original raiser folds and I can either 5 bet jam or flat and see a flop. In this instance, I 5 bet jammed and got called by AA. I kind of laughed because what are the chances right. But then the flop came with 2 spades (I had the ace of spades) and I could feel that it was going to be one of those sick hands. Sure enough, turn and river were both spades. How crazy is that?

No. but I once lost with kings against kings, all-in pre-flop. That was on The Gaming Club, which is long gone.

 

[freedom4L]

I probably have, but my Aces have been cracked by other aces in huge spots before multiple times and im feeling pretty damn salty for that luck to not have been evened out