The probability of being dealt two equal hands in a row in Texas Hold'em depends on the number of players at the table and the number of decks used in the game.
For a standard game of Texas Hold'em with nine players and a deck of 52 cards, the probability of being dealt the exact same hand twice in a row is about 1 in 16,000. The formula to calculate this probability is:
P = (1/C(n,2)) * (1/1326)
Where P is the probability of being dealt the same hand twice in a row, C(n,2) is the number of possible combinations of two
poker hands among n players (in this case, 9 players), and 1/1326 is the probability of receive any specific hand (there are 1326 possible two-card combinations in a standard 52-card deck).
Replacing the values:
P = (1/C(9,2)) * (1/1326) P = (1/36) * (1/1326) P = 0.00000226
Therefore, the probability of being dealt two equal hands in a row in Texas Hold'em is approximately 0.000226%.