#### TheNoob

##### Visionary

- Joined
- May 2, 2008

- Total posts
- 540

I found this somewhere in the interweb to explain pot odds:

*The pot is $30, and the cost of the call is $10. The pot odds in this situation are 30:10, or 3:1 when reduced. To get the percentage, we add 3 plus 1 get a sum of 4. Now we divide 1 by 4, giving us 0.25, or 25 percent.*

This made sense to me.

So with my example it would be:

*The pot is $1.95, and the cost of the call is $1.45. The pot odds in this situation are 1.95:1.45, or 1.35:1 when reduced. To get the percentage, we add 1.35 plus 1 get a sum of 2.35. Now we divide 1 by 2.35, giving us 0.42, or 42 percent.*

Where the heck is my error here?

Part of my problem here if I can't do simple math and understand simple pot odds.