pot odds in 4bet pot

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hadi10

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Greetings and respect.

Please guide how to solve the following problem:

The pot is $80 and the opponent has bet $40 and we 3-bet $100 and the opponent has 4-bet $220:

What is the percentage of the opponent's 4 bets compared to the pot?

What are our pot odds?

Thank you
 
H

hadi10

Rising Star
Bronze Level
Joined
Sep 19, 2023
Total posts
3
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30
H

hadi10

Rising Star
Bronze Level
Joined
Sep 19, 2023
Total posts
3
NO
Chips
30
The ratio of 4 bets to the total pot is 64% because:

(Note that we want to know what percentage of the opponent's 4 bets is of the total pot. So, from the opponent's point of view, we must calculate the total pot)


According to the formula, the total pot is: 3 times the opponent's bet + the amount of the pot before the opponent's bet

(here, since we are counting from the point of view of 4 bettors, so we are the opponent and we had raised to $100)


(Actually, we did not raise 100 dollars, first we called 40 dollars and then raise 60 dollars. So our raise is 60 dollars)

(60*3) + 40 + 40 + 80 = 160 + 180 = 340 is the total pot


Now he has 4-bet $220, so 220 divided by 340 is 64%

That means he has 4-bet 64% of the pot.

--------------------------------------------------------------

Our pot odds are also 1 to 2.7 or 27%. Because:

$80 was in the pot + opponent raised $40 + (we called him $40 and then raised $60) + (opponent called us $60 and then raised $160)

as a result:
The total pot is 440 and we have to call 160 dollars. It means 160 to 440 or 1 to 2.7 which is 27%


What is your opinion? Are my calculations wrong?


thank you
 
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