Z
Zer0-0uts
Rock Star
Silver Level
I posted thread somewhat similar to this one when I first joined. Although this post is the same subject matter, the questions in this one delve deeper into hand odds and pot odds. For this post I want to outline how I understand things to be, and then have someone look it over and tell me yea or nay. Ok let's get into it.
Now the way I understand things to work is like this. Lets say for this example that there is a total of $15 in the pot. The villain leads out and bets $10 on the flop making the pot $25. I believe that I am behind in the hand, but I am open ended for a total of 8 outs. I take the 8 outs and multiple them by 4. This gets me to 32. Then I add one to get 33. This means if I see this hand to the end I have a 33% chance of making the straight. 100/33=3.030303, so I am basically looking at 3 to 1 odds against making the hand.
Now I look at the pot odds I am being offered. It will cost me $10 to win $25. So $25/$10=2.5. Now I put that together. The odds are 3 to 1 against making the hand and I am only being offered 2.5 to 1 on my money. The odds against me making the hand are greater than the odds I am being offered for my $10 call. I should fold.
Now let's look at the same situation only this time there is the $15 in the pot. The villain puts in a $10 bet. There is one caller before it gets to me. That brings the pot total to $35. It cost me $10 to call. Now the pot is offering me 3.5 to 1 on my call. Again the odds are 3 to 1 against me making my straight, but this time the pot is offering me 3.5 to 1 on my money. I should call.
Does all this sound right? What if anything do I have wrong here with the way I am looking at things? Thanks in advanced.
Now the way I understand things to work is like this. Lets say for this example that there is a total of $15 in the pot. The villain leads out and bets $10 on the flop making the pot $25. I believe that I am behind in the hand, but I am open ended for a total of 8 outs. I take the 8 outs and multiple them by 4. This gets me to 32. Then I add one to get 33. This means if I see this hand to the end I have a 33% chance of making the straight. 100/33=3.030303, so I am basically looking at 3 to 1 odds against making the hand.
Now I look at the pot odds I am being offered. It will cost me $10 to win $25. So $25/$10=2.5. Now I put that together. The odds are 3 to 1 against making the hand and I am only being offered 2.5 to 1 on my money. The odds against me making the hand are greater than the odds I am being offered for my $10 call. I should fold.
Now let's look at the same situation only this time there is the $15 in the pot. The villain puts in a $10 bet. There is one caller before it gets to me. That brings the pot total to $35. It cost me $10 to call. Now the pot is offering me 3.5 to 1 on my call. Again the odds are 3 to 1 against me making my straight, but this time the pot is offering me 3.5 to 1 on my money. I should call.
Does all this sound right? What if anything do I have wrong here with the way I am looking at things? Thanks in advanced.