This is a discussion on Questions for the more advanced players within the online poker forums, in the Cash Games section; I have a couple questions for those that are actually students of hold 'em and are at the more advanced levels with regards to knowledge 


#1




Questions for the more advanced players
I have a couple questions for those that are actually students of hold 'em and are at the more advanced levels with regards to knowledge of the game.
First, I was rummaging around in some old threads last night, just looking for something interesting and I came upon a thread where a player was bitching about an opponent in an online casino being dealt pocket aces 2 consecutive hands. From what I have seen so far this person complains a lot so the thread didn't really strike me until I got to a reply where another poster spat out some numbers and came up with odds of 48,000 and change to 1 of this actually happening. This number as I recall was based on the odds of it happening in one game then doubled or something similar. This confused me and here's why. Statistically, isn't the chance of being dealt a particular hand, be it AA or 88, the same for each hand dealt. The act of gathering played cards, shuffling, cutting, and dealing are all factors that are completely detatched from the game and are indvidual random events that contribute to the unpredictability of the dealt cards. Correct me if I'm wrong, but doesn't that mean, when simplified, that the odds of being dealt a particular hand no matter the rank don't fluctuate with number of consecutive hands? Doesn't that also mean that pocket aces have an equal statistical probability of being in the hole on every single hand that is dealt? Given of course that no other mitigating factors are changed such as number of players at the table. If what I am thinking is correct then why all the complaining from people when opponents are dealt consecutive pocket pairs in online play where RNG's are used? The only factor that seems to me would affect the probability of pairs would be the number of players in the game. Am I completely wrong or right? Thanks for reading this long post and in advance for your thoughts on this. 
#2




The odds of gettin a specific hand 2 times in a row will always be larger than just getting it once. This is with anything in life that have mathmatical odds.
To make it simple. If you have 101 odds on something. The odds of you getting it 2 times is 201. The odds of getting it 2 times in a row would be even larger. 
#3




But isn't that "statistically speaking", not true...I mean I understand that it is improbbable...but each dealing of the cards is a single solitary act that irrespective of the previous hands can come up any 2 cards. I get the concept that it may "seem" less likely that it will happen, but when dealing with an inanimate, manipulated object, like a deck of cards it seems to me like there are too many variables for any outcome to be accurately predicted. Its all realative....
I am off to the net in search of what I am looking for, I will post back. Maybe I am just making this more complex than in actually is. BTW, VegasGrinder, thanks for the reply. I would like to know, however, how one would come to this conclusion regarding this specific example. I'm not looking for a simplification of it, or someone to say "you're wrong." I want to be shown how I'm wrong and how to correctly figure the odds the right way. 
#4




in our noble poker freeroll last week i got pocket aces two hands in a row at the beginning of the tourney ( and i showed them ) then the cards went down hill from there. i would rather get pocket AA towards the end of the tourney rather than the beginning. ( i went allin with them both times and no one called,i did that cause everytime i play sloplay them someone catches something and beats me) 65% 35% percent of the time.
buckster436 
#5




I got pocket Q's last night back to back in a ring game  lost on both to a river though. I agree that I'd rather have the good cards come later as if you get the nuts early the cards tend to fall off quickly. In a SNG I played last week the first hand I got was 22, flop was 22A. Quads to start out and it was the last real hand I got...

#8




Well,
I read a post where some person sad the got them 3 times in a row. I myself have gotten them two times in a row more than once. The other day playing Omaha. I got AK 10 times in like 340 hands and QJ almost as many times during that 40 hands as well. Obviously not as rare as getting AA 2 or 3 times in a row. But, still very odd. Worse part is none of them won. Talk about a bad streak. LOL The next day I doubled up from what I had lost. I felt better. 
#10




Knowledge for you:
The odds of drawing AA on any one hand is 1/221. It is a single event. The odds of drawing AA on the next hand are also 1/221, I agree. It is also a single event. However, when you look at the odds of drawing AA 2 times in a row, then you are looking at a single event, that event being AA coming up 2 times in a row, and the odds of that is 1/221 times 1/221, or 1/48841. If you want to look at the single event of AA coming up 3 times in a row, the it is 1/10,793,861, 
#11




Quote:
Chance of any one ace is 4/52. Chance of getting another ace is 3/51. Chance of getting pocket aces (or any other) is 4/52 X 3/51, or 0.4% Chance of getting aces two hands in a row is 4/52 X 3/51 X 4/52 X 3/51, or .002%. 
#12




Quote:

#14




re: Poker & Questions for the more advanced players
diablo is right. the events are independent of each other. its like rolling a dice 1/6 odds of hitting a 6. if you roll it again you have the exact same odds of hitting a 6, 1/6. If i could remember my statistics terminology it would be a bit clearer.

#18




Thank god people finally got what I was saying. And no bpazjr13, you don't have to be a genius to figure out this particular problem, which is good because you got it wrong so there's still hope for ya. Unless you're smarter than Albert Einstein, your dice throwing analogy is 100% wrong. When a dice is tossed, the chance of it hitting any one particular number is 1 in 6. On the second, third, fourth, all the way through 3,000,000th toss, the chance of it hitting the same number doesn't change. Same with cards.
BTW, I would have left that first sentence out of my post if you hadn't made the inference that other posters were less than intelligent for disagreeing, especially since they were correct. 
#19




so..you are saying that rolling a 6 once has the same chance as rolling two 6's in a row does?
that makes absolutely no sense at all... roll number 1  you roll a six 1/6 of the time roll number 2  you roll another six 1/36 of the time roll number 3  you roll another six 1/216 of the time not... rolling 3 sixes in a row has a 1/6 chance of happening 
#20




The odds of it happening are 1 in 6 on each individual roll. They are all seperate occourances independant of one another. How can the probability change? Does the dice still have six sides? If it does the answer is 1 in 6. On 6000 rolls, the 6 will come up close to 1000 times. Thus, a 1 in 6 chance.

#21




re: Poker & Questions for the more advanced players
yes in 6000 rolls it will come around 1,000 times but the odds of it coming up 1,000 times in a row is not 1000/6000 (1/6)..that is close to impossible
you are wrong....go get an education in probabilities 
#22




Are you going to apologize when you are proved wrong? Why do you assume I am uneducated? So far, you have proven that you are just an asshole, not an educated man. My goal now is to prove positive that you aren't as sharp as you think you are. If, and that is a huge IF, I am wrong (which I am all but positive I'm not), I will admit it. Will you be a big enough person to do the same? Probably not.

#23




I hate to say it, but the original poster of this thread is wrong. Sorry, not trying to be offensive but bpazjr13 has it correct. The odds of hitting a 6 is 1/6 the first time and every 6000 rolls you will roll close to 1000 6's, but it wouldn't be in a row. The odds of hitting 1000 straight 6's is in the billions/trillions:1
Sorry, you could probably look it up on the internet under like learn probabilities or something. 
#24




Quote:

#26




If this is boring you don't post here, troll.
If I am wrong, then explain this. How do the chances of being dealt hand XX differ from deal #1 to deal #2. Should be simple. Same number of cards in the deck, same number of dealt cards (2), same number of players at the table. 93.762% of people on the internet pull statistics out of their ass 
#27




"Not quite. If the odds of something happening are 10:1, the odds of it happening again are 100%. The odds of it happening consecutively are 10:1 x 10:1 = 100:1"
seems so simple to me to understand this, why dont you diablo? I'll repost this for you which explains everything Knowledge for you: The odds of drawing AA on any one hand is 1/221. It is a single event. The odds of drawing AA on the next hand are also 1/221, I agree. It is also a single event. However, when you look at the odds of drawing AA 2 times in a row, then you are looking at a single event, that event being AA coming up 2 times in a row, and the odds of that is 1/221 times 1/221, or 1/48841. If you want to look at the single event of AA coming up 3 times in a row, the it is 1/10,793,861, exactly what Four Dogs said but different numbers http://www.thebankrollbuilder.com/fo...hp?p=4350#4350 check it out...another guy from his site knows what he is talking about 
#28




re: Poker & Questions for the more advanced players
First of all, the headline of that thread which you linked to is cute. I would love for you to say something like that to me from across the table. Second, I asked a question...simple enough, but from the moment you posted here you were condescending and rude, at which point I stopped listening to what you said. You may in fact, be right this time. However, you will forever be a dickhead. You're demeanor is no way to get respect from others or have them listen to your responses.

#29




Quote:

#30




thats bull shit diablo, i didnt say one thing to you until you said something about not having to be a genius . read over the posts and I said something too xdman or whoever and I care more than less that you think im a dickhead, i gave you a straight out answer to your question and you ignored it and you are so wrong still
go get an education in probabilities and not being an ignorant little punk...and I will say that to you here, across the table, or anywhere you please yes...swing, we got that covered, thanks 
#32




I think the point that needs made is the odds of getting dealt a certain hand back to back are irrelevant to the game! Only use would be if you were trying to establish some kind of cheating, or the legitamacy of a poker site by tracking a couple hundred thousand hands! The odds do not differ AT ALL as to which hand you get dealt from hand to hand. If they did that would mean that A. either the cards were not being properly shuffled B. That there is some kind of "pattern" to how cards are dealt(there isn't)! Here is a QOUTE "The cards dealt on any poker hand are, for practical purposes, completely random and independent of the cards dealt on any previous hand" Mason Malmuth Small Stakes Hold'em. Main problem is our brains are taught to recognise patterns it is at the core of how we learn. THERE IS NO PATTERN AS TO HOW CARDS ARE DEALT! Now posting in other forums about people being stupid when you are having a discussion means you are looking for people who share your incorrect ideas, trust me even if you think I am full of shit there are very intelligent people here. Only place you will find smarter posters is twoplustwo so unless you have a quote from that site keep it to yourself!

#34




great...glad you shared that with me....yea, we get that the two hands are separate events, but when you calculate getting AA back to back..that is a single event also, and the possiblities of getting AA, then AA is not the same as getting a single AA is what im trying to explain sort of

#35




re: Poker & Questions for the more advanced players
Quote:
if the you are talkin two events of the same probability, then its just [odds of the event happening]^[how many times the event happens in a row] ...im surprised i remember this... dropped data management a while ago 