Originally Posted by StealthLSU
obviously depends on if you hold that card, but off the top of my head, assuming you don't have that suit.
13/50*12/49*11/48*10/47*9/46
.0006045 or .06045% That seems right, someone correct me if I'm wrong.


I think your close, but I don't think there should be 5 variables, because the first card has a 100% chance of being the suit that the other four will have to be. And in the situation I described, there are a total of four hole cards that are not diamonds. So if the first card is a diamond, there are then 47 cards in the deck, 12 of witch are diamonds. So would the math be
12/47*11/46*10/45*9/44 ?????
I think that right or close, which would put the odds of the board flushing at around .2773% chance of the board flushing. I think this is close or on the right track, but any other ideas are absolutely welcome.