This is a discussion on Chances of getting the exact same hand? within the online poker forums, in the General Poker section; Just thought i would log onto titan poker have a quick game, after sitting down at two tables the first hand was exactly the same. 


#1




Chances of getting the exact same hand?
Just thought i would log onto titan poker have a quick game, after sitting down at two tables the first hand was exactly the same. Just wondering what people think the chances of these sort of things are seems odd to me

#4




about the same odds as me winning a hand..

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I guess what I'm trying to say is I THINK what the OP is asking is the odds of getting ANY hand twice in a row. I would think, then, that your odds of getting it the first time is 100% as we are just interested in matching our first hand with the second one and you have this chance literally every time you are dealt a hand. Having said all that, I have no idea what the correct formula is (and you may even be right for all I know), but I don't think it's anywhere near as rare as 0.002%. I will concede it's a fairly rare event; just not THAT rare. Now, if OP IS asking the odds of getting EXACTLY this specific hand twice in a row, then I believe your formula is correct. 
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So chance of 2nd hand being a PP (preusming 1st hand is already a PP) = 6/1326 chance of 2nd hand bieng a non PP (presuming 1st hand is non PP) 16/1326 [(13/91)*(6/1326)] + [(78/91)*16/1326)] = 1/91 1/91*100 = 1.0989...% chance of getting the same hand on one table presuming the hand has already been dealt on the other. If you wanted to include suitedness it's the same formula but a longer version. 
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Moe P.S. These hands were on the same table... NOT multitabling. 
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#17




haha well actually, the probably that in two consecutive hands you would be dealt the six of hearts as the left card and the six of diamond as the right card is 0.00001422% [(1/52)*(1/51)] ^ 2
I personally would prefer aces or kings, but still very interesting lol 
#18




I think the 0.0377% answer is correct... there are 51*52=2652 different starting hands (including suits and order) and all have the same chance of appearing, 1/2652 = 0.0377%.
At the first table you're simply going to get one, it doesn't matter which. At the second table there's 0.0377% chance to get a specific hand, e.g. the same one as the first table. 
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I guess my calculation would be as you were logging on to the computer you ask "What's the probability that I will get a 6 of hearts and 6 of diamonds in the same order in the first 2 hands?" 
#21




re: Poker & Chances of getting the exact same hand?
It's not that crazy. 1/52 * 1/51. The first hand is irrelevant unless you are talking about odds of getting a specific matching hand. But for your 2nd hand to match your first is just 1 in 2652.

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#24




its quite rare to get the same hand on two diff tables at the same time on the same client dnt think thats happened to me tho it has happend that iv got the same pocket cards on carbon and pokerstars at the same time

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If you don't care about the order, but want the same suits, you multiply the above number by 2. It gets more complicated if you don't care about suits, and even more complicated if you don't care about suits and it's not a paired hand. Basically the problem mathematically is in the ambiguity of the question. You just need a more clearlydefined situation. 
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re: Poker & Chances of getting the exact same hand?
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I don't think that's what the original question was asking, but maybe that's what the comment was about. 
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