Originally Posted by BlueNowhere
Odds of getting it once x odds of getting it once. So here there are 6 combos of 66 and 1326 total combos. 6/1326 = 1//221 (1/221)*(1/221) = (1/221)^2 = 1/48841 = 0.002% chance.


Well, as you know, I'm definately (and, defiantly ) NOT a math guy, so my thinking could be way off, but this seems wrong. OP isn't asking about odds of getting this, or any, specific hand backtoback, but just the odds of getting the exact same hand twice in a row. It seems to me (and my potentially flawed logic) that your first part (odds of getting it once) doesn't apply.
I guess what I'm trying to say is I THINK what the OP is asking is the odds of getting ANY hand twice in a row. I would think, then, that your odds of getting it the first time is 100% as we are just interested in matching our first hand with the second one and you have this chance literally every time you are dealt a hand.
Having said all that, I have no idea what the correct formula is (and you may even be right for all I know), but I don't think it's anywhere near as rare as 0.002%. I will concede it's a fairly rare event; just not THAT rare. Now, if OP IS asking the odds of getting EXACTLY this specific hand twice in a row, then I believe your formula is correct.