smells_flushy
Rock Star
Silver Level
Hey folks, I just have a quick question about pot odds of a hand i saw a moment ago.
Daniel Negreanu has Ac Kd, while Yarlagadda holds Qd Qc in a flop of:
4c 8c 9c
The probability of each person winning is shown by the wsop as 49% and 51% for Daniel Negreanu and Yarlagadda respectfully.
However, I counted 14 outs for Daniel Negreanu to make his winning hand (three kings, three Aces, and 8 clubs).
Using my quick method of calculation, i did this:
2(14 outs x 2) = 56%
So shouldn't the percentages be in Negreanu's favour with 56%, while Yarlagadda is underdog with 44%?
Is something wrong with my method of probability calculation? If not, what accounts for such a big difference in percentages between my results and that of the WSOP's percentages?
Thanks for all input
Daniel Negreanu has Ac Kd, while Yarlagadda holds Qd Qc in a flop of:
4c 8c 9c
The probability of each person winning is shown by the wsop as 49% and 51% for Daniel Negreanu and Yarlagadda respectfully.
However, I counted 14 outs for Daniel Negreanu to make his winning hand (three kings, three Aces, and 8 clubs).
Using my quick method of calculation, i did this:
2(14 outs x 2) = 56%
So shouldn't the percentages be in Negreanu's favour with 56%, while Yarlagadda is underdog with 44%?
Is something wrong with my method of probability calculation? If not, what accounts for such a big difference in percentages between my results and that of the WSOP's percentages?
Thanks for all input