Math Wizard Needed

[wagon596]

First I hope this is the right place to ask this question, if not it will be moved.

I have two random hole cards, if I see the hand all the way to the river, what are the odds I'll not pair one of my hole cards? Go for it you math gurus out there.

 

[Jillychemung]

You will be dealt 2 unpaired cards 94.12% of the time
Your 2 unpaired cards will flop a pair 32.4% of the time
Your 2 unpaired cards will flop two pair 2% of the time
Your 2 unpaired cards will have 1 card paired on the turn 12.8% of the time
Your 2 unpaired cards will have 1 card paired on the river 13% of the time

See https://www.pokerstrategy.com/strategy/various-poker/texas-holdem-probabilities/ for all your probability question including all the math behind it.

Here is another quote I stole from that other forum

'Since you have two unpaired cards, there are 50 unknown cards from which the board cards can come, and 6 of these 50 would pair one of your hole cards and 44 would not. So going card by card on the 5-card board, the probability of NOT pairing at least one of your hole cards by the river is easily seen to be given by:
(44/50) * (43/49) * (42/48) * (41/47) * (40/46) = 130,320,960 / 254,251,200

Subtracting from one yields the desired prob of pairing at least one of your hole cards by the river = 48.7432272%.'

 

[cwdignus]

First I hope this is the right place to ask this question, if not it will be moved.

I have two random hole cards, if I see the hand all the way to the river, what are the odds I'll not pair one of my hole cards? Go for it you math gurus out there.

I was very curious to know in what you will use, in practice, this knowledge of probability ... I consider you a great player and your ability to recure in the game with few chips impresses me a lot

 

[pdcactus1]

one, two, three..crunch.. three

How many licks does it take to get to the center of a tootsie pop? 3 your answer is one in 6 chance of hitting. so 20%

:driver::icon_sile:lollypop:​

 

[wagon596]

You will be dealt 2 unpaired cards 94.12% of the time
Your 2 unpaired cards will flop a pair 32.4% of the time
Your 2 unpaired cards will flop two pair 2% of the time
Your 2 unpaired cards will have 1 card paired on the turn 12.8% of the time
Your 2 unpaired cards will have 1 card paired on the river 13% of the time

See https://www.pokerstrategy.com/strategy/various-poker/texas-holdem-probabilities/ for all your probability question including all the math behind it.

Here is another quote I stole from that other forum

'Since you have two unpaired cards, there are 50 unknown cards from which the board cards can come, and 6 of these 50 would pair one of your hole cards and 44 would not. So going card by card on the 5-card board, the probability of NOT pairing at least one of your hole cards by the river is easily seen to be given by:
(44/50) * (43/49) * (42/48) * (41/47) * (40/46) = 130,320,960 / 254,251,200

Subtracting from one yields the desired prob of pairing at least one of your hole cards by the river = 48.7432272%.'

Thanks, I created a shortcut to the site.

 

[lexyyxel]

good