What if it was 27 instead of J7? It is argumented that 27 is better than 77.interesting question. i think, and i might be wrong, j7 > 77 because you have some blockers with the jack and you don't have any with the 7. so, you block some combinations of 10j, kj, and aj, meaning it's less likely to hit the turn. plus, if they did have a hand like those, the jack gives you 2 pair, so they're effectively drawing to 3 outs or more if they have a back door draw. ex: if they have kj and the turn is a 10, they pick some extra equity with an open-ended straight + k pair.
77 doesn't block anything and all over cards have the full equity to hit on the turn or river. and they also get full equity if they hit a back door draw on the turn. so, same example, lets say villain has kj and the turn is a 10. they have an full equity to hit their oesd + 2 over card pairs.
surprisingly, when i put up both situations against the same 16.4 range,What if it was 27 instead of J7? It is argumented that 27 is better than 77.
Hi everyone!
So, I heard having a pair on board (E.G. J7 on Q73) board is much better than having an underpair (E.G. 77 on Q63 board). Why? Aren't they equal in strength?
Let's flip the sides. If you were the preflop aggressor which one would you be more happy to c-bet? I would probably c-bet J7 because even when we are behind to some overpairs to 7, most of our 36% equity is realisible equity(about 20%) and we also can barrel turn also when we don't make our hand, whereas with 88 we only hope for an 8 to continue barreling.To be a little more scientific about it I plugged in a Q73 rainbow board in equilap and assigned Villain a range, which I think, most people will C-bet as the preflop raiser. The range was 77+, 33, ATs+, A7s, KQs, Q9s+, 97s, 87s, ATo+, A7o, KQo, QTo+. This might seem wide, but if it was a late position open, I actually think, a lot of people would C-bet even more. And against this range 88 and J7 have an almost identical 36-37% equity. Folding either hand to a standard C-bet like half pot would therefore be a mathematical mistake.