This is a discussion on Odds of making pair with AK ? within the online poker forums, in the Learning Poker section; You have 6 outs. So, can you use "Rule of 2 and 4", but for 5 cards? Rule of 10? Basically, 60% odds to getting an 


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Odds of making pair with AK ?
You have 6 outs. So, can you use "Rule of 2 and 4", but for 5 cards?
Rule of 10? Basically, 60% odds to getting an A or K? P(another A or K) = 6/50 + 6/49 + 6/48 + 6/47 + 6/46 = .62 ? 
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I found this online, since there are many smarter people then me on poker odds. But this seems logical
In every case, there are 6 cards (the three remaining Aces, and the three remaining Kings) that will pair one of your hole cards. Not pairing with the first flop card = (50  6) / 50 Not pairing with the second flop card = (49  6) / 49 Not pairing with the third flop card = (48  6) / 48 Not pairing with the turn = (47  6) / 47 Not pairing with the river = (46  6) / 46 The probability of not pairing either hole card = 44/50 x 43/49 x 42/48 x 41/47 x 40/46 = 0.512568 The probability of pairing at least one of the hole cards = 1  0.512568 = 0.487432 
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re: Poker & Odds of making pair with AK ?
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Looks like it's 50/50 to hit a pair if you go to the river. 
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Not positive but since you watch a lot of WSOP videos ever noticed how they show you your winning percentage (they even adjust based on someone folding a previous out).
Unless your all in, each street has to take into account how many cards the dealer has left in their hand to get a more accurate estimate. Never really looked into the pairing of a whole card by river all I know its about 32% chance of pairing on the flop 
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The other players cards are ignored as you don't know what they are. The odds are adjusted when you do know, but you can't subtract the other players cards since you don't know whether or not they contain an A or K. 
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re: Poker & Odds of making pair with AK ?
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