Originally Posted by firstcrack
Thank you. I have contributed a direct solution to the problem using the simple probability ratio of number of desired outcomes divided by the total possible outcomes, if you are still curious. Not as simple and elegant as the original solution submitted by Rhombus, I think, but still interesting. (IMHO)


Thanks for the input, FirstCrack. I'll definitely look at. Maybe not tonight, I'm not in the math mood but I will very soon. Maybe we'll educate the OP in the other thread a little bit, as well as anyone else interested.