This is a discussion on correct formula for pot odds. within the online poker forums, in the Learning Poker section; Just checking that I am correct here. I have always calculated pot odds as (Size of Pot) / (Cost of Call) meaning that if the 


#1




correct formula for pot odds.
Just checking that I am correct here.
I have always calculated pot odds as (Size of Pot) / (Cost of Call) meaning that if the pot is 200 and the call costs 50 you are getting 4:1 pot odds. however I have read a few artices and seen iti n a few books where its calculated as (Size of Pot) + (Cost of Call) / (Cost of Call) which is the same as 1+ {(Size of Pot) / (Cost of Call)} meaning that if the pot is 200 and the cost of the call is 50 then the pot odds are 5:1 (because once you call the pot gets bigger) Am I correct in thinking that the first method is the one to use? 
#2




I found I prefer Phil Gorden's definitions best and he says 5:1 is the better way to treat it. The overriding concept is to think that once you bet that $50 it is no longer your money and now belongs to the pot to be won. So the pot to be won = (Size of Pot) + (Cost of Call) which makes the pot odds = 5:1 instead of 4:1.
He then defines Break Even Percentage or the % of time that you need to win a hand, in relation to the money in the pot, to make a call worthwhile and your BEP then = 1/(pot odds + 1) x 100 or for your example 1/(5+1) * 100 = 17%. Then by the rule of 4 and 2 you know you need at least 4 outs on the flop (=16% but close enough)) and and least 8 outs on the turn (16%) to justify a call. I have found using Phil's pot odds/bep/rule of 4&2 in combination easy to use at the table (live or online) to justify calls, and found it seems to be effective in limiting my calls to a reasonable % that work out. 
#4




re: Poker & correct formula for pot odds.
If you want to work with percentages, like Phil Gordon does, you need to include your bet into the pot. Otherwise, it would be wrong to do so.
% basically means "this was multiplied by 100", e.g. Code:
8 outs = 8 x 2 = 16% (rule of 2) 16 1 16% =  =  100 6,25 Code:
6,25  1 = 5,25 
#7




Quote:
What I mean is if you are getting either 4:1 or 5:1 on the same call and you took it over a 1K hand sample, you are going to be better off taking the 4:1 odds over the 5:1 odds side of the issue. 
#8




re: Poker & correct formula for pot odds.
theres a nice poker odds free website http://www.pokernews.com/pokeroddscalculator.htm

#9




interesting
thx for the info i always thought something totaly different so thx for letting me know ill try this in my calculations for futue games instead of just thing of it as geting some 1 po for catching now i canm tell them i had pot odds lol gl to all

#10




badass... I'm guessing you're playing in micro buyins at Pokerstars. Maybe it has something to do with their marketing campaign.
Getting the right odds on the flop to make the call...... Now work in the implied odds.... how much of their stack are you going to grab if you make your hand? Maybe this is why some donks call me with gutters on the flop??? lol 
#11




To look at this in a different way is intresting and definative, if you bet 50 four times and win 250 one time you are 50 in profit, if you bet 50 five times and win 250 once you break even.
Stu i thought you were the master of stats, are you setting quiz questions and is there a prize? 