Question about Side Pots

Scenario:
Blinds $5/$10
Player A: $50
B:$40
C:$75
D:$20
A:sb, B:bb, C:raises to$25, D:calls All-in, A:calls $20, B: folds

Main Pot:$10, Side Pot:$70

Flop: 2d,7h,Jh

A:checks, C:Bets $25, A:folds

Main Pot: $35 Side Pot: $70

C:shows Kh,Qh, D:shows As,Ac

Turn:3c
River:10d

Does Player C get $35 from the main pot or Player D gest Side Pot + Main Pot?
I know that all-in player can only double up, just want to make sure that i get everything right.

You are correct, player D gets all the money up to $20 from each player, in this case that is $70.

You've labelled them backwards, which I think is probably the source of confusion - $70 isn't the side pot, it's the main pot. The one that everyone can win.

The side pot is the one between players that had more money than the all-in player. Before the flop A and C have both put in $5 more than C, so a $10 side pot is created.

When C bets and A folds on the flop, C takes the $10 in the side pot (it's $10, not $35, because his second bet was never called). Give that to him when A folds and don't think about it again.

That leaves C and D to contest the main pot. At the end of the hand, D takes the $70 main pot because his aces beat C's king high.

The pots are always awarded in the reverse order to that in which they were created. In this hand we created the main pot, then the side pot. We award the side pot, then work out who won the main pot.

There was a good lengthy discussion on side pots a few days ago...

https://www.cardschat.com/forum/general-poker-13/unfair-ps-tournament-rule-142892/