The Odds Of Pocket Aces
Does anyone know how to claculate the odds
of 2 players in a 10 handed game getting pocket aces in the same hand? I saw it happen 2 nites in a row recently and got curious. I know the odds of getting pocket aces are 4/52*3/51=1/221 and the odds of 2 players getting pocket aces playing heads up is 4/52*3/51*2/50*1/49=1/270,725. Since there are 45 2 player combinations possible in a 10 handed game, I'm wondering if the answer is maybe 270,725/45 or about once every 6017 hands. If you know the correct calculation or even think you know it, I'd appreciate your telling me.