Need Help Calculating Odds

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Phosphorous

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I need help calculating odds... but it's kind of an odd request.

For Hold 'Em, I'd like to know the odds of the following occurring, using your 2 cards and the community 5 cards (all cards):
-3 pair
-6 card straight
-7 card straight
-6 card straight flush
-7 card straight flush
-6 card flush
-7 card flush
-"Super" full house (4 of a kind + 3 of a kind)

Can anyone help or recommend me to someone?
 
Sardonix

Sardonix

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ummm i'm not sure why the odds of these hands even matter :confused: Im not sure if you can calculate this with pokerstove or not. you can try it but im not going to waste my time.... pokerstove.com
 
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Phosphorous

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When playing a dealer-calls-it cash game, I want to introduce a new spin on regular HoldEm... playing all 7 cards with expanded hand rankings. The only problem is, I need to know the relative rarity of all of the hands.

BTW, the "super" full house happened to me the other day. I had pocket 8's and flopped 6-8-6. Thinking I was set with a full house I tried to milk the hand and got screwed on the River. Turn and River were both 6's. I knew the other guy had a better kicker for the Quad 6's we shared.
 
Stu_Ungar

Stu_Ungar

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When playing a dealer-calls-it cash game, I want to introduce a new spin on regular HoldEm... playing all 7 cards with expanded hand rankings. The only problem is, I need to know the relative rarity of all of the hands.

BTW, the "super" full house happened to me the other day. I had pocket 8's and flopped 6-8-6. Thinking I was set with a full house I tried to milk the hand and got screwed on the River. Turn and River were both 6's. I knew the other guy had a better kicker for the Quad 6's we shared.

Might be more trouble than its worth.

Why try and reinvent the wheel?
 
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WarEagle1266

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Well, a seven card flush would be (13/52)*(12/51)*(11/50)*(10/49)*(9/48)*(8/47)*(7/46) which would be .0000128%, or 1 in 77,963.03. A super full house would be (52/52)*(3/51)*(2/50)*(1/49)*(48/48)*(3/47)*(2/46) which is .000000133%, or 1 in 7,503,941.67. But, if you want the hand rankings, it would be 3 pair, 6 card straight, 6 card flush, 6 card straight flush, 7 card straight, 7 card flush, Super full house, 7 card straight flush.
 
Snowmobiler

Snowmobiler

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I need help calculating odds... but it's kind of an odd request.

For Hold 'Em, I'd like to know the odds of the following occurring, using your 2 cards and the community 5 cards (all cards):
-3 pair
-6 card straight
-7 card straight
-6 card straight flush
-7 card straight flush
-6 card flush
-7 card flush
-"Super" full house (4 of a kind + 3 of a kind)

Can anyone help or recommend me to someone?



I know a mental doctor taking new patiants ;)




Snow :cool:
 
Makwa

Makwa

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The odds are that if you are focused on these imaginary hands and these answers, you will get killed at the tables. No offense. :eek:
 
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