Originally Posted by StackThemUp
6 boats in a row? We should ask diablo what the odds of that are!! Now is it the same each new deal or are we working out a combined event?
Hmmm, when did diablo become our resident statistician? I know your relatively new here, so I'll excuse you for not being up on your ancient history. Go back and read Questions for the more advanced players
and The stupid AA thing continued. Warning: This is long (http://The stupid AA thing continued. Warning: This is long). This is realy the same problem but with different variables.
The odds of getting just one Full House dealt to you with 2 down and 5 on the board are 3,473,184(different ways to make a Full House) / 133,784,560(total combinations of hands possible) = .026 or about 37:1
2IAR = .0007 = 1,478:1
3IAR = 1.76 x 10^-5 = 56,894:1
4IAR = 4.57 x 10^-7 = 2,188,298:1
5IAR = 1.19 x 10^-8 = 84,165,335:1
6IAR = 3.09 x 10^-10 = 3,237,128,296:1
Suffice it to say that tenbob was very lucky indeed.
Too bad it didn't happen just one more time.
7IAR = 8.03 x 10^-12 =124,504,935:1
I think it would have been safe to say that this event had never ever occured in the entire history of this world, or any other world in any other universe or dimension real or imaginary.
Remember The Heart of Gold, the starship in Douglas Adams book The Hitchikers Guide to the Galaxy? It ran off an engine called an infinite imbrobability drive. When engaged, the ship would simultaneously pass through every point in the universe but would result in distressingly improbable events which would occur in and around the ship. Examples given were losing limbs, turning into penguins, planets spontaneously becoming fruitcakes, nuclear missiles metamorphosing into sperm whales and bowls of petunias and last but not least improbable, tenbob flopping
6 boats in a row.
PS- bob, do you mind if I rub your head for luck?