Originally Posted by JMcCabe
This is a pretty common question that I thought about quite a bit when I started playing Hold'em (a long time ago).
As far as I'm aware, there is no way to get 27 outs. The scenario I outlined is the most you can have (24 on the flop, 26 on the turn).
This can occur with a number of suited connectors or gappers when you flop on open-ended straight flush draw on a paired board vs. an underpair to the board and your cards.
For example, if you had 8sJs on a flop of 9sTsTd against 2h2d, and the turn was the 3c, you would again have the 8 straight outs, 7 remaining flush outs, 3 jacks, 3 nines, 3 eights, or 2 treys.
Glad to help.
WoW, I've been working on this almost all day now, just because it got me going and I wanted to know how many different ways that you could end up with 26 outs, and I believe, I was right, it is 168
different ways of ending up with 26 outs with suited connectors...such as (K,Q)(Q,J)(J,10)(10,9)(9,8)or(8,7)(below or above these connectors wont work, such as (A,K), or (5,6)). BUT..., I didn't take into account "gappers, as you discussed, and WOW, is all I can say. That changes the total A LOT!
And the example you give using Js,8s, also is a good example, however, there can be a total of 80
different ways of getting 26 outs with Js8s!!
I have figured out that a suited (5,8), will give you 8
different ways of getting 26 outs, and (6,9), will give you 24.
With (7,10), you can get 26 out's 48
different ways, and (9,Q), equals 120
, "26 outers", and you end up with the most ways of getting 26 outs with a suited (K,10)...168
ways! If you add all those up, with suited gappers you could expect to have 26 outs, 448 different ways
If you add that to the 168 ways of getting 26 outs with suited connectors, you end up with 616
different ways of ending up with "26 outs on the river"!
(I think that would be a good title to my book....
(If I can't get rich playing, I'll have to write a BOOK!) LOL
TY JMcCabe, (I'll put you in it for some credit...LOL)