Pots Odds Question!?
First and foremost, I like to say that I'm a new member of the CardsChat community. I've only began playing poker with real money
for almost a year. I've lost almost 2000 of my own money so I decided to take a break and learn poker theoretically. I subscribed to DeucesCracked only shorty and I've been watching wiltontilt math videos. On episode 2, he gave an example on pot odds
The pot is a 1000 $ and you have 500 $ to call to win. If you win once, that's plus 1000, but if you lose twice -500 x 2 = -1000.
Assuming this is a heads up match and when you make the call for 500, the total pot will be 1500. Altogether I've put forth 750. If I called the 500 and lost twice, wouldn't I of lost 250 in the 3 games?
500 of the pot before, 500 of his raise and my 500 call (1500).
-500 twice (-1000) added to his/ her 750 money (the one profitable game/ call)- might of been confusing.
I'm still 250 down.
He said 2:1 dog is break-even and any better and I'll win money, any lower and I'll lose money.
But I see 2:1 dog a still losing act.
Can someone please explain this to me. I don't know if he made a mistake or if I'm not just understanding it. Thanks.