Originally Posted by soadwes
1. 999XX, with no pairs above 9 or straight flush possibility
2. AKQJ10 suited, with 93 of same suit; this gives you Q high flush
3. does not exist! lol i can't figure out the last answer
1 and 2 correct (though 2 would be Ace high flush)
3 - 993, and 2 other unpaired cards lower than an 8. You'd have full house, 9's over 3's, and no-one else could have higher as there are no cards on board bigger than 9 to make trips.
Edit - no F*@% it - if someone else has got the other 9 and matches other card they'll beat you. 99322's no good cos they could have 22 -oh,i don't know either!