Originally Posted by rob5775
No, you didn't explain. How did you come up with the percentages in bold?


Actually, it looks like I miscalculated. Here's the math:
9% chance of one of your opponents holding a better Ace (i.e. A9, AT, AJ, AQ or AK).
There are a total of 1326 starting hand combinations (52x51 / 2)
When you already hold one Ace, there are exactly 12 ways [(3x4 + 4x3) / 2] for your opponent to hold A9, 12 ways to hold AT, 12 ways to hold AJ, 12 ways to hold AQ and 12 ways to hold AK.
That's a total of 60 out of 1326 possible hands, or 4.5%.
The same is true for opponent number 2, so the correct total is ~9%.
10% chance of one of your opponents holding a pocket pair that is not 88 or AA
There are 6 ways (4x3 / 2) to be dealt any specific pocket pair that is not 88 or AA.
6 x 11 = 66 out of 1326 possible hands, or 5.0%.
Dito for the other opponent, so the correct total is ~10%.
1% chance of one of your opponents holding AA or 88.
There are 3 ways (3x2 / 2) to be dealt 88 or AA when one A and one 8 is gone.
3 x 2 = 6 out of 1326 possible hands, or 0.5%
Dito for the other opponent, so the correct total is ~1%.