Im not sure I totally agree with this. We figure outs for the maximum number of outs. and yes sometimes others are holding some or some are burned by the dealer. So those hands have less actual outs. Its never more than the maximum outs. So how would it even out.
So actual outs on a 10 outer on average is probably only an 8 outer.
I would be interested in seeing a formula and some tests with this theory
No, your outs are *always* against the pool of unknown cards.
You're outs are always against the 50 unknown cards pre-flop.
You're outs are always against the 47 unknown cards on the flop.
You're outs are always against the 46 unknown cards on the turn.
Times that other people are holding your outs you have a decreased likelihood of hitting, and times when they do not hold your outs you have in increased likelihood of hitting. These even out because it's always the same pool of 50 cards that are randomly distributed.
The odds of other people holding cards you need does not change. It is a static number. Your opponent *always* has 2 random cards of 50 unknown cards. VS eight opponents, they *always* have 16 random cards of the unknown 50 cards.
Over the long run people will be holding your outs as often as they should, and they won't be holding your outs as often as they should. You cannot see their cards so you cannot readjust those numbers. You can only calculate known information, and that information is the pool of cards you cannot see which are randomly distributed.