| This is a discussion on Pot Odds Question within the online poker forums, in the Learning Poker section; I am slightly confused on calculating ones odds to hit an out with one and two cards to come. I have seen them calculated in ... |
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| Pot Odds Question I am slightly confused on calculating ones odds to hit an out with one and two cards to come. I have seen them calculated in different ways- one way treats both streets eparately and the other way tries to incporporate ones estimate of how much one might have to bet on the next street into the calculations. Has any one seen calcuation like these or have I just massively misunderstood and it is really just a question of taking a street by street approach? Last edited by Donkus Maximus : 7th May 2009 at 2:28 AM. |
| Play Texas Hold'em Online Poker | Pot Odds Question | |
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| Quote:
The part in quotes is from: http://www.tightpoker.com/poker_odds.html |
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| re: Pot Odds Question poker velutha is correct. Your odds will never change from a bet. I believe what you are talking about is combining a couple things. The odds are always the same regardless of a bet, but you will have to pay more to see them if you aren't all in. For example, if you have TcTd on a flop of 3dKs4h, and your opp. has kc2c you have two outs, the other two tens. Your odds of catching one by the river is ~2*4=8 and by the turn its' ~2*2=4. So if you go All in right now (which is not a great play obviously) you will get to see both streets for the same price. if on the other hand you call a raise, you will still have to call another raise on the turn to see the river. So if you are getting the right odds if you get to see both cards, you may have to make another call on the turn which will mean you aren't getting the right odds to make the call. I hope that made sense |
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