Hello everyone, I was just trying to figure out what the odds are of all five of the community cards being the same suit. This doesn't really have any strategic implications that I can really think of, more just me being angry that my Ace pairing in a knockout Heads-up opportunity being foiled by the board deciding make every community card a diamond causing a split pot. Any with any idea of what the odds are when no one is showing any diamonds, I'd be interested to find out.

Thanks for the help,
RedskinRunner

obviously depends on if you hold that card, but off the top of my head, assuming you don't have that suit.

13/50*12/49*11/48*10/47*9/46

.0006045 or .06045% That seems right, someone correct me if I'm wrong.

I actually saw this happen today at an Sng, the board was JKA9T of hearts. What was even more sick was the dude sitting next to me had the Q of hearts

Originally Posted by StealthLSU

obviously depends on if you hold that card, but off the top of my head, assuming you don't have that suit.

13/50*12/49*11/48*10/47*9/46

.0006045 or .06045% That seems right, someone correct me if I'm wrong.

I think your close, but I don't think there should be 5 variables, because the first card has a 100% chance of being the suit that the other four will have to be. And in the situation I described, there are a total of four hole cards that are not diamonds. So if the first card is a diamond, there are then 47 cards in the deck, 12 of witch are diamonds. So would the math be

12/47*11/46*10/45*9/44 ?????

I think that right or close, which would put the odds of the board flushing at around .2773% chance of the board flushing. I think this is close or on the right track, but any other ideas are absolutely welcome.

According to Wikipedia, the odds of making 4 to a flush by the turn are .0156. So multiply that by 9/48 to get .002925. Which is about 3 times in 1000 hands, or 333-1.

Originally Posted by RedskinRunner325

I think your close, but I don't think there should be 5 variables, because the first card has a 100% chance of being the suit that the other four will have to be. And in the situation I described, there are a total of four hole cards that are not diamonds. So if the first card is a diamond, there are then 47 cards in the deck, 12 of witch are diamonds. So would the math be

12/47*11/46*10/45*9/44 ?????

I think that right or close, which would put the odds of the board flushing at around .2773% chance of the board flushing. I think this is close or on the right track, but any other ideas are absolutely welcome.

yup, you are right, knew I missed something

What about the odds of three people flopping a flush. That happened to me recently and of course my q high wasn't good enough. That has to be crazy odds right?