wasnt sure where to post this... curiosity more than anything really

#1 24th August 2008, 8:56 PM

hi. this is just something i was wondering. im sure there are some math people that would have an answer. approximately how many hands should you be dealt before you expect a pair? im on hand #44 right now and i have in the past gotten into the 60s. thanks for your responses

#2 24th August 2008, 9:00 PM

I beilive its 1 in 17 hands should be a PP.

#3 24th August 2008, 9:32 PM

Yeah 1 in 17 sounds right. Odds of any particular pair are 1 in 220 so that would be 13 possible pairs, 13/220 is about 1/17.

That doesn't mean you wont have long streaks. Sometimes you'll not see any for far longer than 17 hands, sometimes you'll 2 or 3 in a row. Just that on average it should be 1/17.

On a related note someone on fulltilt once became convinced that it was rigged and I was a hacker or superuser when I got AA 3 times in ten hands and a total of 10 pocket pairs in about 30 hands. Sometimes you just get lucky. More often you remember the bad streaks but that was a pretty memorable good one.

#4 24th August 2008, 10:00 PM

i would agree. you do remember the bad streaks more for sure. i was just wondering how far past the statistics i had gone with 44 hands. btw, i did get a pp....22 about 10 hands later. ty for the responses.

#5 24th August 2008, 10:28 PM

As stated a pair is 1/17 so its 16/17 you won't be dealt a pair. Plug(16/17)^44 into a calculator. Going your first 44 hands or more without a pair will happen about 7% of the time.

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