Splitting the pots fairly

#1 14th November 2008, 3:12 PM

Question for poker people out there:

Take the situation; it's $100 to call and player A and B have called. However, player C only has $75 dollars and decides to go ALL-IN. Player D also calls $100- so the total amount in the pot is $375.

At the showdown, Player C actually wins with 2 pair, followed by player B with 1 pair. So how much does Player C get?? Surely he doesn't win the whole $375, since he didn't call with the full amount??

help!

#2 14th November 2008, 3:18 PM

They take $75 from players A and B and add it to the $75 player c has put into the put also player D puts in $75 to that pot as well. $25 from player a,b,d goes into the pot they are trying to win without player C.

#3 14th November 2008, 3:22 PM

So Player C would win $300 (including the $75 he put in), and player B (who came 2nd) would win the remaining $75??

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