| This is a discussion on A Poker Quiz Question within the online poker forums, in the General Poker section; I was watching poker the other day and i thought of this situation and thought i could make it into a question. Can anyone think ... |
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| A Poker Quiz Question I was watching poker the other day and i thought of this situation and thought i could make it into a question. Can anyone think of a situation where 2 players are in the pot, 1 has the 2nd nuts based on their cards, the other has the 2nd nuts based on their cards. But 1 hand is superior over the other? Give your answer like this Board: X X X X X Hole Cards: X X X X I have thought of 1 and think it is the only possible answer but we will see |
| Play Texas Hold'em Online Poker | A Poker Quiz Question | |
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Board. A K K X X Hole Cards: A A (2nd nuts to pock kings) A K (2nd nuts to pock aces) |
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| re: A Poker Quiz Question This is a devious question. The game would just about have to be Omaha Hi/Lo, possibly Stud hi/lo. Thats the only place where 2 2nd nuts could exist, but even then we're begging definitions. There is something real wrong here tho. There could be thousands of hands that fit this incomplete scenario. example in addition to KaBooms; board KQ678 rainbow player 1 kq45 player 2 kq23 the nut hand would be A29T in any HI/LO game this would be 2 hands with 2nd nuts. the 2 pair are there to keep the players in the pot to get to the 2nd nuts question? Last edited by dj11 : 28th November 2007 at 6:30 PM. |
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| dj, you're misunderstanding this. this is applying to NL hold em only look at my example Board: 4c 5c 6c X X Hole Cards: player 1 has Ac7c, player 2 has 2c3c player 1 can only be beat by one hand in the deck: 2c3c. player 2 can only be beat by one hand in the deck. 7c8c. they both have the 2nd nuts but only one hand is the winner |
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| well if it's hold 'em there's been 3 so far, but as I notice there's XXXX for the hole cards, implying that the game is indeed Omaha. This seems like even easier, adding rags to all previous hold 'em hands gives the same scenarios, so that's at least 3. |
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that represents 2 sets of hole cards for holdem, for 2 players |
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| re: A Poker Quiz Question I have another contender! Board 6h 8d Td Jd Qd Player 1 4s 9d Player 2 3c Ad Player 1 has straight flush Q - 9 so can only be beaten by someone holding Ad Kd. Player 2 Has the nuts flush, but can be beaten by someone holding 9d. It's true that someone could beat player 2 with either Kd 9d or Kd and anything else. However, player 2 can only lose to someone holding 9d so technically it's irrelevant whether that play also has Kd or not. The cards NOT highlighted could be pretty much anything, so argueably there are dozens of combinations. |
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