25 OUTS IS THE MOST POSSIBLE OUTS ACCORDING TO MY CALCULATIONS

My calculation is 25 outs is the most outs you can have

Here is my scenario:
My hole cards: 6 diamonds 7 diamonds
Opponent's hole cards: 2 diamonds 2 hearts
Flop: 4 hearts 4 diamonds 5 diamonds
Turn: 9 of clubs
YOU WILL HAVE:
8 outs for the flush (technically 6 outs for flush, 2 outs for straight flush) and the reason it is 8 outs instead of 9 is because opponent has one of the diamonds (if you give opponent a different non-diamond 2, if the 2 of diamonds comes will give him a boat so same difference)
6 outs for a larger pair (3 outs for hitting a 6, 3 outs for hitting a 7)
6 outs for a straight (3 outs for hitting a 3, 3 outs for hitting an 8) *note any diamond would be for the straigh flush so that is why it is 6 and not 8 and has already been accounted for above.
5 outs for counterfeit ( 3 outs for hitting a 5, making opp two pair no good and 2 outs of hitting a 9, making a higher two pair than opp)
This was all done personally, let me know if this is correct or you think there can be more.

Looks about right, but technically what you have calculated is the number of "clean" outs - those which do not also improve your opponent`s hand. Such an accurate calculation is only possible in an all-in situation when the cards are on their backs and you know your opponent`s exact holding.

More often, in a real life situation, you will not have that information and will be calculating the total number of outs, but using your judgement to discount those which are doubtful, based on your assessment of the opponent`s likely hand or range of hands.

Try with 10♠ J♠ vs 2♠ 2♥:

Flop: 9♠ Q♠ 9♥

Our outs:
8 x spades
3 non spade 8's
3 non-spade K's
3 J's
3 10's
3 Q's

I can only get 23 outs maximum for the flop, but i'm certain it's been calculated before, if the A♣ comes on the turn, we pick up 3 extra outs to the counterfeit, so 26 total

@ Egon i took those into consideration actually, and this is a scenario which all cards are turned over and a heads up deck with all 44 cards being available after the 4 hole cards and 4 community cards.
The only cards that he can benefit from is a 4 for a fullhouse and a 2 for a fullhouse, and those werent outs listed to benefit my hole cards. The rest of the cards would make you lose, but they werent listed as my outs, so this is accurate.

@ben_rhyno Yeah you can change the cards and get the same result, that is the exact scenario actually, but 26 was close but not right, because you forgot if ace of clubs come, all three of the rest of aces are outs however one was accounted for the flush already the ace of spades, so then ends up being 25. But thank you, this confirms that I have done my math right. I really do believe 25 is the maximum you can have.
Great insight guys, thanks a lot.

23 outs plus 2 for a chop

edit: nvm, i'm a donk. yep 25 outs. just stoved it, we are actually a favorite. 53.4% equity.

@cheap trix thanks for confirming
i just downloaded stove saw it on another poker thread. but from my math, in a HU situation ( 4 Hole Cards and 4 Community Cards) with 44 cards left, 25 outs divided by 44 = 56.8% according to a calculator lol, but I am not sure if my math is wrong or that pokerstove is innaccurate, your take?

ahh ha! i was on the right path to begin with. the difference is because three 5's give us a tie.
so we have 22 outs 3 for a chop... was originally thinking 2 nines gave us a chop, lol.

and i just put it in poker stove and it says 3.41% for a tie, but there is no cards for a chopped pot
if a 9 comes out, you will still have a 7 kicker he will have a 2 kicker, im starting to question the validity of pokerstove.

a rivered 5 gives you a chop

hahaha sweeet dude ur awesome, yah i posted my last post before your second to last post and then i ran out of poker posts cuz im new to this site, so i had to make this account. Yep, you and poker stove is right, the 3 fives give the chopped pot, 22 outs and 3 for a chop is correct.

I saw an Omaha example once where it was possible to have the best hand on the turn against 3 opponents, but have 0% chance to win once the river card comes. A very contrived example, but still possible.

It was something like bottom set against a collection of 2 pair/straight draws/flush draws, and someone holding your case card needed to get quads.

Contrived? Totally standard.